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49-25/9x^2=0
Domain of the equation: 9x^2!=0We multiply all the terms by the denominator
x^2!=0/9
x^2!=√0
x!=0
x∈R
49*9x^2-25=0
Wy multiply elements
441x^2-25=0
a = 441; b = 0; c = -25;
Δ = b2-4ac
Δ = 02-4·441·(-25)
Δ = 44100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{44100}=210$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-210}{2*441}=\frac{-210}{882} =-5/21 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+210}{2*441}=\frac{210}{882} =5/21 $
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